What is the general solution for 1+sin(θ)=1+cos(θ) ?

The general solution for 1+sin(θ)=1+cos(θ) is θ= pi/4+pin

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1+sin(θ)=1+cos(θ)

1 + sin (θ) = 1 + cos (θ)

θ = \frac{π}{4} + πn

Solution steps

1 + sin (θ) = 1 + cos (θ)

Subtract

1 + cos (θ)

from both sides

sin (θ) - cos (θ) = 0

Rewrite using trig identities

tan (θ) - 1 = 0

Move

1

to the right side

tan (θ) = 1

General solutions for

tan (θ) = 1

θ = \frac{π}{4} + πn

tan (x) = tan (4 0^{\circ}) tan (5 0^{\circ})

tan (x) + tan (2 x) = 0

3 cos (2 θ) + 2 = - cos (θ)

cos (x) = \frac{7.2}{9.4}

sin (θ) = - 2 - cos (θ)

What is the general solution for 1+sin(θ)=1+cos(θ) ?
The general solution for 1+sin(θ)=1+cos(θ) is θ= pi/4+pin