What is the general solution for cos(2x-pi/(14))=0 ?

The general solution for cos(2x-pi/(14))=0 is x=pin+(2pi)/7 ,x=pin+(11pi)/(14)

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cos(2x-pi/(14))=0

cos (2 x - \frac{π}{14}) = 0

x = πn + \frac{2 π}{7}, x = πn + \frac{11 π}{14}

Solution steps

cos (2 x - \frac{π}{14}) = 0

General solutions for

cos (2 x - \frac{π}{14}) = 0

2 x - \frac{π}{14} = \frac{π}{2} + 2 πn, 2 x - \frac{π}{14} = \frac{3 π}{2} + 2 πn

Solve

2 x - \frac{π}{14} = \frac{π}{2} + 2 πn : x = πn + \frac{2 π}{7}

Solve

2 x - \frac{π}{14} = \frac{3 π}{2} + 2 πn : x = πn + \frac{11 π}{14}

x = πn + \frac{2 π}{7}, x = πn + \frac{11 π}{14}

2 = 2 tan (x)

\frac{sin ( x )}{1 + cos ( x )} + cot (x) = 2

4 cos (2 θ) + 16 cos (θ) + 4 = 9 cos (θ)

sin (θ) = \frac{7 π}{3}

tan (x) \cdot cos^{2} (x) - tan (x) = 0

What is the general solution for cos(2x-pi/(14))=0 ?
The general solution for cos(2x-pi/(14))=0 is x=pin+(2pi)/7 ,x=pin+(11pi)/(14)