What is the general solution for cos^2(θ)-sin(θ)cos(θ)=0 ?

The general solution for cos^2(θ)-sin(θ)cos(θ)=0 is θ= pi/2+2pin,θ=(3pi)/2+2pin,θ= pi/4+pin

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cos^2(θ)-sin(θ)cos(θ)=0

cos^{2} (θ) - sin (θ) cos (θ) = 0

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn, θ = \frac{π}{4} + πn

Solution steps

cos^{2} (θ) - sin (θ) cos (θ) = 0

Factor

cos^{2} (θ) - sin (θ) cos (θ) : cos (θ) (cos (θ) - sin (θ))

cos (θ) (cos (θ) - sin (θ)) = 0

Solving each part separately

cos (θ) = 0 or cos (θ) - sin (θ) = 0

cos (θ) = 0 : θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

cos (θ) - sin (θ) = 0 : θ = \frac{π}{4} + πn

Combine all the solutions

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn, θ = \frac{π}{4} + πn

x, cos (2 x) + cos (x) = 0

2 sin (θ) + cos (2 θ) = 1

sin (π t) = 0

8 sin^{3} (x) = 8 sin (x)

sin^{2} (x) + cos^{2} (x) = sin (x)

What is the general solution for cos^2(θ)-sin(θ)cos(θ)=0 ?
The general solution for cos^2(θ)-sin(θ)cos(θ)=0 is θ= pi/2+2pin,θ=(3pi)/2+2pin,θ= pi/4+pin