What is the general solution for 2cos^2(t)+3cos(t)-5=0 ?

The general solution for 2cos^2(t)+3cos(t)-5=0 is t=2pin

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2cos^2(t)+3cos(t)-5=0

2 cos^{2} (t) + 3 cos (t) - 5 = 0

t = 2 πn

Solution steps

2 cos^{2} (t) + 3 cos (t) - 5 = 0

Solve by substitution

cos (t) = 1, cos (t) = - \frac{5}{2}

cos (t) = 1 : t = 2 πn

cos (t) = - \frac{5}{2} :

No Solution

Combine all the solutions

t = 2 πn

6 cos^{2} (x) + 7 sin (x) - 8 = 0

3 csc (x) = 2

4 csc^{2} (x) - 25 = 0

sin (θ) = - \frac{4}{5}, \frac{3 π}{2} < θ < 2 π

4 cos (x) + sin^{2} (x) = 3 cos^{2} (x) + 2

What is the general solution for 2cos^2(t)+3cos(t)-5=0 ?
The general solution for 2cos^2(t)+3cos(t)-5=0 is t=2pin