What is the general solution for 5tan(B)+sqrt(13)=0 ?

The general solution for 5tan(B)+sqrt(13)=0 is B=-0.62475…+pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5tan(B)+sqrt(13)=0

5 tan (B) + 13 = 0

B = - 0.62475 \dots + πn

Degrees

B = - 35.79575 \dots^{\circ} + 18 0^{\circ} n

Solution steps

5 tan (B) + 13 = 0

Move

13

to the right side

5 tan (B) + 13 = 0

Subtract

13

from both sides

5 tan (B) + 13 - 13 = 0 - 13

Simplify

5 tan (B) = - 13

5 tan (B) = - 13

Divide both sides by

5

5 tan (B) = - 13

Divide both sides by

5

\frac{5 tan ( B )}{5} = \frac{- 13}{5}

Simplify

tan (B) = - \frac{13}{5}

tan (B) = - \frac{13}{5}

Apply trig inverse properties

tan (B) = - \frac{13}{5}

General solutions for

tan (B) = - \frac{13}{5}

tan (x) = - a \Rightarrow x = arctan (- a) + πn

B = arctan (- \frac{13}{5}) + πn

B = arctan (- \frac{13}{5}) + πn

Show solutions in decimal form

B = - 0.62475 \dots + πn

tan^{2} (x) = 3 tan (x)

2 cos^{2} (x) - 2 = 0

sin (θ - \frac{π}{4}) - 1 = 0

tan^{2} (x) + csc^{2} (x) - 3 = 0

cos^{2} (x) - cos (x) = 2

What is the general solution for 5tan(B)+sqrt(13)=0 ?
The general solution for 5tan(B)+sqrt(13)=0 is B=-0.62475…+pin