What is the general solution for 8cos(x)-8sin(x)=0 ?

The general solution for 8cos(x)-8sin(x)=0 is x= pi/4+pin

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8cos(x)-8sin(x)=0

8 cos (x) - 8 sin (x) = 0

x = \frac{π}{4} + πn

Solution steps

8 cos (x) - 8 sin (x) = 0

Rewrite using trig identities

8 - 8 tan (x) = 0

Move

8

to the right side

- 8 tan (x) = - 8

Divide both sides by

- 8

tan (x) = 1

General solutions for

tan (x) = 1

x = \frac{π}{4} + πn

sin (4 x) cos (x) - sin (x) cos (4 x) = \frac{1}{2}

arccos (x) = \frac{1}{2}

3 sin^{2} (θ) - 7 sin (θ) + 2 = 0

9 sin^{2} (θ) + 14 cos (θ) - 12 = 5 cos (θ) - 1

4 sec^{2} (x) - 2 = 0

What is the general solution for 8cos(x)-8sin(x)=0 ?
The general solution for 8cos(x)-8sin(x)=0 is x= pi/4+pin