What is the general solution for solvefor x,z=arcsin(xy) ?

The general solution for solvefor x,z=arcsin(xy) is x=(sin(z))/y

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solvefor x,z=arcsin(xy)

solve for

x, z = arcsin (x y)

x = \frac{sin ( z )}{y}

Solution steps

z = arcsin (x y)

Switch sides

arcsin (x y) = z

Apply trig inverse properties

arcsin (x y) = z

arcsin (x) = a \Rightarrow x = sin (a)

x y = sin (z)

x y = sin (z)

Solve

x y = sin (z) : x = \frac{sin ( z )}{y}; y \neq = 0

x y = sin (z)

Divide both sides by

y; y \neq = 0

x y = sin (z)

Divide both sides by

y; y \neq = 0

\frac{x y}{y} = \frac{sin ( z )}{y}; y \neq = 0

Simplify

x = \frac{sin ( z )}{y}; y \neq = 0

x = \frac{sin ( z )}{y}; y \neq = 0

x = \frac{sin ( z )}{y}

2 cos (x) - 2 = 0

4 sin^{2} (θ) - 13 sin (θ) + 9 = 0

23 cos^{2} (x) = sin (x)

4 cos^{4} (θ) - 5 cos^{2} (θ) + 1 = 0

x, cos (x) = sin (2 x)

What is the general solution for solvefor x,z=arcsin(xy) ?
The general solution for solvefor x,z=arcsin(xy) is x=(sin(z))/y