What is the general solution for tan^2(x)-3=0,0<= x<= 2pi ?

The general solution for tan^2(x)-3=0,0<= x<= 2pi is x= pi/3 ,x=(4pi)/3 ,x=(2pi)/3 ,x=(5pi)/3

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tan^2(x)-3=0,0<= x<= 2pi

tan^{2} (x) - 3 = 0, 0 \leq x \leq 2 π

x = \frac{π}{3}, x = \frac{4 π}{3}, x = \frac{2 π}{3}, x = \frac{5 π}{3}

Solution steps

tan^{2} (x) - 3 = 0, 0 \leq x \leq 2 π

Solve by substitution

tan (x) = 3, tan (x) = - 3

tan (x) = 3, 0 \leq x \leq 2 π : x = \frac{π}{3}, x = \frac{4 π}{3}

tan (x) = - 3, 0 \leq x \leq 2 π : x = \frac{2 π}{3}, x = \frac{5 π}{3}

Combine all the solutions

x = \frac{π}{3}, x = \frac{4 π}{3}, x = \frac{2 π}{3}, x = \frac{5 π}{3}

4 sin (θ) + 22 = 0

5 cos (θ) = - 53 sin (- θ)

sin (x) = - \frac{15}{17}

tan (θ) = 7

0 = sin (x^{2})

What is the general solution for tan^2(x)-3=0,0<= x<= 2pi ?
The general solution for tan^2(x)-3=0,0<= x<= 2pi is x= pi/3 ,x=(4pi)/3 ,x=(2pi)/3 ,x=(5pi)/3