What is the general solution for 3cos(2θ)=0 ?

The general solution for 3cos(2θ)=0 is θ= pi/4+pin,θ=(3pi)/4+pin

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3cos(2θ)=0

3 cos (2 θ) = 0

θ = \frac{π}{4} + πn, θ = \frac{3 π}{4} + πn

Solution steps

3 cos (2 θ) = 0

Divide both sides by

3

cos (2 θ) = 0

General solutions for

cos (2 θ) = 0

2 θ = \frac{π}{2} + 2 πn, 2 θ = \frac{3 π}{2} + 2 πn

Solve

2 θ = \frac{π}{2} + 2 πn : θ = \frac{π}{4} + πn

Solve

2 θ = \frac{3 π}{2} + 2 πn : θ = \frac{3 π}{4} + πn

θ = \frac{π}{4} + πn, θ = \frac{3 π}{4} + πn

4 cos (2 x) + 2 sin (x) = 1, 0^{\circ} \leq x \leq 36 0^{\circ}

3 csc (θ) + 5 = 0

cos (\frac{x}{3}) - cos (\frac{x}{15}) = 0

(2 cos (x) - 3) (2 sin (x) + 1) = 0

y, x = π - arcsin (y)

What is the general solution for 3cos(2θ)=0 ?
The general solution for 3cos(2θ)=0 is θ= pi/4+pin,θ=(3pi)/4+pin