What is the general solution for 4sqrt(3)sin(3θ+20)=4cos(3θ+20) ?

The general solution for 4sqrt(3)sin(3θ+20)=4cos(3θ+20) is θ=-20/3+pi/(18)+(pin)/3

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4sqrt(3)sin(3θ+20)=4cos(3θ+20)

43 sin (3 θ + 20) = 4 cos (3 θ + 20)

θ = - \frac{20}{3} + \frac{π}{18} + \frac{πn}{3}

Solution steps

43 sin (3 θ + 20) = 4 cos (3 θ + 20)

Rewrite using trig identities

43 tan (3 θ + 20) = 4

Divide both sides by

43

tan (3 θ + 20) = \frac{3}{3}

General solutions for

tan (3 θ + 20) = \frac{3}{3}

3 θ + 20 = \frac{π}{6} + πn

Solve

3 θ + 20 = \frac{π}{6} + πn : θ = - \frac{20}{3} + \frac{π}{18} + \frac{πn}{3}

θ = - \frac{20}{3} + \frac{π}{18} + \frac{πn}{3}

tan (x) = \frac{300}{400}

tan^{2} (x) - tan (x) = 0, (180, 270)

2 sin^{2} (θ) + 3 cos (θ) - 3 = 0

3 sin (x) tan (x) + 3 sin (x) = 0

sin (z) + cos (z) = 2

What is the general solution for 4sqrt(3)sin(3θ+20)=4cos(3θ+20) ?
The general solution for 4sqrt(3)sin(3θ+20)=4cos(3θ+20) is θ=-20/3+pi/(18)+(pin)/3