What is the general solution for 4sec(θ)+2sqrt(3)=sec(θ) ?

The general solution for 4sec(θ)+2sqrt(3)=sec(θ) is θ=(5pi)/6+2pin,θ=(7pi)/6+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4sec(θ)+2sqrt(3)=sec(θ)

4 sec (θ) + 23 = sec (θ)

θ = \frac{5 π}{6} + 2 πn, θ = \frac{7 π}{6} + 2 πn

Solution steps

4 sec (θ) + 23 = sec (θ)

Solve by substitution

sec (θ) = - \frac{2 3}{3}

sec (θ) = - \frac{2 3}{3} : θ = \frac{5 π}{6} + 2 πn, θ = \frac{7 π}{6} + 2 πn

Combine all the solutions

θ = \frac{5 π}{6} + 2 πn, θ = \frac{7 π}{6} + 2 πn

2 cos (3 x) - 3 = 0

cos^{2} (x) - 8 cos (x) - 1 = 0

cos (x) + 2 = 1

2 cos (2 θ) = - 1

3 cot^{2} (x) = 3 cot (x)

What is the general solution for 4sec(θ)+2sqrt(3)=sec(θ) ?
The general solution for 4sec(θ)+2sqrt(3)=sec(θ) is θ=(5pi)/6+2pin,θ=(7pi)/6+2pin