What is the general solution for cos^2(x)-3/4 =0,0<= x<= 2pi ?

The general solution for cos^2(x)-3/4 =0,0<= x<= 2pi is x= pi/6 ,x=(11pi)/6 ,x=(5pi)/6 ,x=(7pi)/6

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cos^2(x)-3/4 =0,0<= x<= 2pi

cos^{2} (x) - \frac{3}{4} = 0, 0 \leq x \leq 2 π

x = \frac{π}{6}, x = \frac{11 π}{6}, x = \frac{5 π}{6}, x = \frac{7 π}{6}

Solution steps

cos^{2} (x) - \frac{3}{4} = 0, 0 \leq x \leq 2 π

Solve by substitution

cos (x) = \frac{3}{2}, cos (x) = - \frac{3}{2}

cos (x) = \frac{3}{2}, 0 \leq x \leq 2 π : x = \frac{π}{6}, x = \frac{11 π}{6}

cos (x) = - \frac{3}{2}, 0 \leq x \leq 2 π : x = \frac{5 π}{6}, x = \frac{7 π}{6}

Combine all the solutions

x = \frac{π}{6}, x = \frac{11 π}{6}, x = \frac{5 π}{6}, x = \frac{7 π}{6}

sin^{2} (x) - sin (x) - cos^{2} (x) = 0

12 cos^{2} (x) + sin (x) - 6 = 0

sin (A) = \frac{3}{5}

tan (θ) = 0.2

sin (x) tan (x) = sin (x), 0 \leq x \leq 2 π

What is the general solution for cos^2(x)-3/4 =0,0<= x<= 2pi ?
The general solution for cos^2(x)-3/4 =0,0<= x<= 2pi is x= pi/6 ,x=(11pi)/6 ,x=(5pi)/6 ,x=(7pi)/6