What is the general solution for sin(3x)=1,0<= x<= 2pi ?

The general solution for sin(3x)=1,0<= x<= 2pi is x= pi/6 ,x=(5pi)/6 ,x=(3pi)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin(3x)=1,0<= x<= 2pi

sin (3 x) = 1, 0 \leq x \leq 2 π

x = \frac{π}{6}, x = \frac{5 π}{6}, x = \frac{3 π}{2}

Solution steps

sin (3 x) = 1, 0 \leq x \leq 2 π

General solutions for

sin (3 x) = 1

3 x = \frac{π}{2} + 2 πn

Solve

3 x = \frac{π}{2} + 2 πn : x = \frac{π}{6} + \frac{2 πn}{3}

x = \frac{π}{6} + \frac{2 πn}{3}

Solutions for the range

0 \leq x \leq 2 π

x = \frac{π}{6}, x = \frac{5 π}{6}, x = \frac{3 π}{2}

x, z = arcsin (\frac{x}{x ^{2} + y ^{2}})

cos (θ) (2 cos (θ) + 1) = 0

2 cot (x) - 2 = 0

1 - 2 sin (x) = 0

3 sec (x) - 4 = 0

What is the general solution for sin(3x)=1,0<= x<= 2pi ?
The general solution for sin(3x)=1,0<= x<= 2pi is x= pi/6 ,x=(5pi)/6 ,x=(3pi)/2