What is the general solution for 0=2sin(θ) ?

The general solution for 0=2sin(θ) is θ=2pin,θ=pi+2pin

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0=2sin(θ)

0 = 2 sin (θ)

θ = 2 πn, θ = π + 2 πn

Solution steps

0 = 2 sin (θ)

Switch sides

2 sin (θ) = 0

Divide both sides by

2

sin (θ) = 0

General solutions for

sin (θ) = 0

θ = 0 + 2 πn, θ = π + 2 πn

Solve

θ = 0 + 2 πn : θ = 2 πn

θ = 2 πn, θ = π + 2 πn

sin (\frac{π}{2} + x) = - cot (x)

tan (A) = - 1

sin (x) = - \frac{5}{8}

2 sin (x) = 1, 0 \leq x \leq 2 π

5 cot (x) + 4 = 9

What is the general solution for 0=2sin(θ) ?
The general solution for 0=2sin(θ) is θ=2pin,θ=pi+2pin