What is the general solution for cos(z+1)=0 ?

The general solution for cos(z+1)=0 is z= pi/2+2pin-1,z=(3pi)/2+2pin-1

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cos(z+1)=0

cos (z + 1) = 0

z = \frac{π}{2} + 2 πn - 1, z = \frac{3 π}{2} + 2 πn - 1

Solution steps

cos (z + 1) = 0

General solutions for

cos (z + 1) = 0

z + 1 = \frac{π}{2} + 2 πn, z + 1 = \frac{3 π}{2} + 2 πn

Solve

z + 1 = \frac{π}{2} + 2 πn : z = \frac{π}{2} + 2 πn - 1

Solve

z + 1 = \frac{3 π}{2} + 2 πn : z = \frac{3 π}{2} + 2 πn - 1

z = \frac{π}{2} + 2 πn - 1, z = \frac{3 π}{2} + 2 πn - 1

4 csc^{2} (\frac{x}{2}) - 6 csc (\frac{x}{2}) - 4 = 0

2 tan (θ) + sec^{2} (θ) = 4

2 sin^{2} (x) + 2 sin (x) - 1 = 0

csc (x) = 7

2 cos (θ) sin (θ) + cos (θ) - 2 sin (θ) = 1

What is the general solution for cos(z+1)=0 ?
The general solution for cos(z+1)=0 is z= pi/2+2pin-1,z=(3pi)/2+2pin-1