What is the general solution for sin^2(θ)-2sin(θ)-3=0 ?

The general solution for sin^2(θ)-2sin(θ)-3=0 is θ=(3pi)/2+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin^2(θ)-2sin(θ)-3=0

sin^{2} (θ) - 2 sin (θ) - 3 = 0

θ = \frac{3 π}{2} + 2 πn

Solution steps

sin^{2} (θ) - 2 sin (θ) - 3 = 0

Solve by substitution

sin (θ) = 3, sin (θ) = - 1

sin (θ) = 3 :

No Solution

sin (θ) = - 1 : θ = \frac{3 π}{2} + 2 πn

Combine all the solutions

θ = \frac{3 π}{2} + 2 πn

5 tan (θ) - 4 = 0

0 = cos (\frac{x}{2})

3 cos (x) - 1 = cos (2 x)

7 cos^{2} (θ) - 9 = - 9 sin (θ)

y, arcsin (y) = x

What is the general solution for sin^2(θ)-2sin(θ)-3=0 ?
The general solution for sin^2(θ)-2sin(θ)-3=0 is θ=(3pi)/2+2pin