What is the general solution for cos^2(x)-1=0,0<= x<2pi ?

The general solution for cos^2(x)-1=0,0<= x<2pi is x=0,x=pi

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cos^2(x)-1=0,0<= x<2pi

cos^{2} (x) - 1 = 0, 0 \leq x < 2 π

x = 0, x = π

Solution steps

cos^{2} (x) - 1 = 0, 0 \leq x < 2 π

Solve by substitution

cos (x) = 1, cos (x) = - 1

cos (x) = 1, 0 \leq x < 2 π : x = 0

cos (x) = - 1, 0 \leq x < 2 π : x = π

Combine all the solutions

x = 0, x = π

tan^{2} (x) + 1 = 2 \cdot tan (x)

\frac{csc ( θ )}{cot ( θ )} = - 2 tan (θ)

2 cos^{2} (θ) + 3 sin (θ) = 0

sin (2 θ) + 3 cos (θ) = 0

2 cot (x) + csc^{2} (x) = 0

What is the general solution for cos^2(x)-1=0,0<= x<2pi ?
The general solution for cos^2(x)-1=0,0<= x<2pi is x=0,x=pi