What is the general solution for 2sec(x)+1=sec(x)+3 ?

The general solution for 2sec(x)+1=sec(x)+3 is x= pi/3+2pin,x=(5pi)/3+2pin

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2sec(x)+1=sec(x)+3

2 sec (x) + 1 = sec (x) + 3

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

Solution steps

2 sec (x) + 1 = sec (x) + 3

Solve by substitution

sec (x) = 2

sec (x) = 2 : x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

Combine all the solutions

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

sin (3 0^{\circ}) = cos (x - 2 0^{\circ})

- 7 sin (x) = 0

2 sin^{2} (x) - 1 = 0, 0 \leq x < 2 π

tan^{2} (x) + 2 tan (x) = - 1

4 csc^{2} (x) - 2 = 0

What is the general solution for 2sec(x)+1=sec(x)+3 ?
The general solution for 2sec(x)+1=sec(x)+3 is x= pi/3+2pin,x=(5pi)/3+2pin