What is the value of sin(135-30) ?

The value of sin(135-30) is (sqrt(6)+sqrt(2))/4

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sin(135-30)

sin (13 5^{\circ} - 3 0^{\circ})

\frac{6 + 2}{4}

Solution steps

sin (13 5^{\circ} - 3 0^{\circ})

Rewrite using trig identities:

sin (13 5^{\circ}) cos (3 0^{\circ}) - cos (13 5^{\circ}) sin (3 0^{\circ})

= sin (13 5^{\circ}) cos (3 0^{\circ}) - cos (13 5^{\circ}) sin (3 0^{\circ})

Use the following trivial identity:

sin (13 5^{\circ}) = \frac{2}{2}

Use the following trivial identity:

cos (3 0^{\circ}) = \frac{3}{2}

Use the following trivial identity:

cos (13 5^{\circ}) = - \frac{2}{2}

Use the following trivial identity:

sin (3 0^{\circ}) = \frac{1}{2}

= \frac{2}{2} \cdot \frac{3}{2} - (- \frac{2}{2}) \frac{1}{2}

Simplify

\frac{2}{2} \cdot \frac{3}{2} - (- \frac{2}{2}) \frac{1}{2} : \frac{6 + 2}{4}

= \frac{6 + 2}{4}

sin (4 5^{\circ}) + cos (4 5^{\circ})

arccos (0.2)

arctan (\frac{3}{3})

cos (12 0^{\circ}) + cos (4 5^{\circ})

cos (11 5^{\circ})

What is the value of sin(135-30) ?
The value of sin(135-30) is (sqrt(6)+sqrt(2))/4