What is the general solution for sqrt(2)sin(θ)=1 ?

The general solution for sqrt(2)sin(θ)=1 is θ= pi/4+2pin,θ=(3pi)/4+2pin

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sqrt(2)sin(θ)=1

2 sin (θ) = 1

θ = \frac{π}{4} + 2 πn, θ = \frac{3 π}{4} + 2 πn

Solution steps

2 sin (θ) = 1

Divide both sides by

2

sin (θ) = \frac{2}{2}

General solutions for

sin (θ) = \frac{2}{2}

θ = \frac{π}{4} + 2 πn, θ = \frac{3 π}{4} + 2 πn

sin (2 x) (csc (2 x) - 2) = 0

tan (x - π) + 2 sin (x - π) = 0

tan (4 5^{\circ}) = \frac{1 - cos ( u )}{sin ( u )}

1 - 2 cos^{2} (x) = 0

4 sin (x) = 1

What is the general solution for sqrt(2)sin(θ)=1 ?
The general solution for sqrt(2)sin(θ)=1 is θ= pi/4+2pin,θ=(3pi)/4+2pin