What is the general solution for sin^2(x)-7cos(x)-7=0 ?

The general solution for sin^2(x)-7cos(x)-7=0 is x=pi+2pin

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sin^2(x)-7cos(x)-7=0

sin^{2} (x) - 7 cos (x) - 7 = 0

x = π + 2 πn

Solution steps

sin^{2} (x) - 7 cos (x) - 7 = 0

Rewrite using trig identities

- 6 - cos^{2} (x) - 7 cos (x) = 0

Solve by substitution

cos (x) = - 6, cos (x) = - 1

cos (x) = - 6 :

No Solution

cos (x) = - 1 : x = π + 2 πn

Combine all the solutions

x = π + 2 πn

3 sin^{2} (x) = sin (x)

2 cos (2 θ) - 3 cos (θ) + 12 = 5 cos (θ) + 7

sin (4 x) - sin (x) = 0

tan (θ) = \frac{7}{5}

sin (t) = \frac{2}{5}

What is the general solution for sin^2(x)-7cos(x)-7=0 ?
The general solution for sin^2(x)-7cos(x)-7=0 is x=pi+2pin