What is the general solution for 2cos(x)-1=0,0<= x<= 2pi ?

The general solution for 2cos(x)-1=0,0<= x<= 2pi is x= pi/3 ,x=(5pi)/3

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2cos(x)-1=0,0<= x<= 2pi

2 cos (x) - 1 = 0, 0 \leq x \leq 2 π

x = \frac{π}{3}, x = \frac{5 π}{3}

Solution steps

2 cos (x) - 1 = 0, 0 \leq x \leq 2 π

Move

1

to the right side

2 cos (x) = 1

Divide both sides by

2

cos (x) = \frac{1}{2}

General solutions for

cos (x) = \frac{1}{2}

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

Solutions for the range

0 \leq x \leq 2 π

x = \frac{π}{3}, x = \frac{5 π}{3}

tan (2 x) = 2

sin (2 x) = cos (2 x) + 1

8 sin^{2} (x) - 2 = 0

y, sin (x) = x (1 + tan (y))

sin (2 x) - sin (x) = 0, (0, 2 π)

What is the general solution for 2cos(x)-1=0,0<= x<= 2pi ?
The general solution for 2cos(x)-1=0,0<= x<= 2pi is x= pi/3 ,x=(5pi)/3