What is the general solution for solvefor x,sin^2(x)=1 ?

The general solution for solvefor x,sin^2(x)=1 is x= pi/2+2pin,x=(3pi)/2+2pin

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solvefor x,sin^2(x)=1

solve for

x, sin^{2} (x) = 1

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

Solution steps

sin^{2} (x) = 1

Solve by substitution

sin (x) = 1, sin (x) = - 1

sin (x) = 1 : x = \frac{π}{2} + 2 πn

sin (x) = - 1 : x = \frac{3 π}{2} + 2 πn

Combine all the solutions

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

tan^{4} (x) - 2 = tan^{2} (x) + sec^{2} (x)

cos (x - \frac{π}{4}) = - sin (x)

sin (x) = \frac{5}{13}, cos (x)

tan (θ) = \frac{11.9}{10}

tanh (x) = \frac{3}{5}

What is the general solution for solvefor x,sin^2(x)=1 ?
The general solution for solvefor x,sin^2(x)=1 is x= pi/2+2pin,x=(3pi)/2+2pin