What is the general solution for (2sin(x)-1)=0 ?

The general solution for (2sin(x)-1)=0 is x= pi/6+2pin,x=(5pi)/6+2pin

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(2sin(x)-1)=0

(2 sin (x) - 1) = 0

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

Solution steps

(2 sin (x) - 1) = 0

Move

1

to the right side

2 sin (x) = 1

Divide both sides by

2

sin (x) = \frac{1}{2}

General solutions for

sin (x) = \frac{1}{2}

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

x, sin (x) = y

cos (2 x) = 1 - 2 sin (x)

- cos (A) - 11 = 2 cos (A) - 9

sin (θ - \frac{π}{3}) - 1 = 0

cos (5 x) = \frac{1}{2}

What is the general solution for (2sin(x)-1)=0 ?
The general solution for (2sin(x)-1)=0 is x= pi/6+2pin,x=(5pi)/6+2pin