What is the general solution for -sin(4x)=0 ?

The general solution for -sin(4x)=0 is x=(pin)/2 ,x= pi/4+(pin)/2

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-sin(4x)=0

- sin (4 x) = 0

x = \frac{πn}{2}, x = \frac{π}{4} + \frac{πn}{2}

Solution steps

- sin (4 x) = 0

Divide both sides by

- 1

sin (4 x) = 0

General solutions for

sin (4 x) = 0

4 x = 0 + 2 πn, 4 x = π + 2 πn

Solve

4 x = 0 + 2 πn : x = \frac{πn}{2}

Solve

4 x = π + 2 πn : x = \frac{π}{4} + \frac{πn}{2}

x = \frac{πn}{2}, x = \frac{π}{4} + \frac{πn}{2}

csc (x) = sec (4 1^{\circ})

sin (x) - sin (3 x) = 0

2 sin^{2} (θ) - 5 cos (θ) + 1 = 0

sec^{2} (x) cos (x) = cos (x), 0^{\circ} < x < 36 0^{\circ}

5 sin (x) - 4 = 2 cos (2 x)

What is the general solution for -sin(4x)=0 ?
The general solution for -sin(4x)=0 is x=(pin)/2 ,x= pi/4+(pin)/2