What is the general solution for 2cos(x-1)=0 ?

The general solution for 2cos(x-1)=0 is x= pi/2+2pin+1,x=(3pi)/2+2pin+1

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2cos(x-1)=0

2 cos (x - 1) = 0

x = \frac{π}{2} + 2 πn + 1, x = \frac{3 π}{2} + 2 πn + 1

Solution steps

2 cos (x - 1) = 0

Divide both sides by

2

cos (x - 1) = 0

General solutions for

cos (x - 1) = 0

x - 1 = \frac{π}{2} + 2 πn, x - 1 = \frac{3 π}{2} + 2 πn

Solve

x - 1 = \frac{π}{2} + 2 πn : x = \frac{π}{2} + 2 πn + 1

Solve

x - 1 = \frac{3 π}{2} + 2 πn : x = \frac{3 π}{2} + 2 πn + 1

x = \frac{π}{2} + 2 πn + 1, x = \frac{3 π}{2} + 2 πn + 1

5 + 6 sin (x) = 0

sin (\frac{π}{2} x) = 0

csc (\frac{θ}{2}) = - \frac{2}{3}

x, - 2 sin (x) + 2 cos (2 x) = 0

sin (- 2 x) = \frac{3}{2}

What is the general solution for 2cos(x-1)=0 ?
The general solution for 2cos(x-1)=0 is x= pi/2+2pin+1,x=(3pi)/2+2pin+1