What is the general solution for 1=tan(c) ?

The general solution for 1=tan(c) is c= pi/4+pin

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1=tan(c)

1 = tan (c)

c = \frac{π}{4} + πn

Degrees

c = 4 5^{\circ} + 18 0^{\circ} n

Solution steps

1 = tan (c)

Switch sides

tan (c) = 1

General solutions for

tan (c) = 1

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

c = \frac{π}{4} + πn

c = \frac{π}{4} + πn

sin (a) = \frac{3}{2}

tan^{2} (x) = 4

sec (x) = 3

2 cos^{2} (x) + 1 = - 3 cos (x)

8 sin (θ) + 5 = 0

What is the general solution for 1=tan(c) ?
The general solution for 1=tan(c) is c= pi/4+pin