What is the general solution for 100cos(30)-200cos(θ)=0 ?

The general solution for 100cos(30)-200cos(θ)=0 is θ=1.12296…+360n,θ=360-1.12296…+360n

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100cos(30)-200cos(θ)=0

100 cos (3 0^{\circ}) - 200 cos (θ) = 0

θ = 1.12296 \dots + 36 0^{\circ} n, θ = 36 0^{\circ} - 1.12296 \dots + 36 0^{\circ} n

Solution steps

100 cos (3 0^{\circ}) - 200 cos (θ) = 0

cos (3 0^{\circ}) = \frac{3}{2}

100 \cdot \frac{3}{2} - 200 cos (θ) = 0

100 \cdot \frac{3}{2} = 503

503 - 200 cos (θ) = 0

Move

503

to the right side

- 200 cos (θ) = - 503

Divide both sides by

- 200

cos (θ) = \frac{3}{4}

Apply trig inverse properties

θ = arccos (\frac{3}{4}) + 36 0^{\circ} n, θ = 36 0^{\circ} - arccos (\frac{3}{4}) + 36 0^{\circ} n

Show solutions in decimal form

θ = 1.12296 \dots + 36 0^{\circ} n, θ = 36 0^{\circ} - 1.12296 \dots + 36 0^{\circ} n

x, y = sin (2 x + 3 y)

cos (θ) = \frac{8}{9}

2 sin (x) - cos (x) = 0, 0^{\circ} \leq x \leq 36 0^{\circ}

8 tan (A) + 3 = 2 tan (A) + 3

cosh (x) = 3

What is the general solution for 100cos(30)-200cos(θ)=0 ?
The general solution for 100cos(30)-200cos(θ)=0 is θ=1.12296…+360n,θ=360-1.12296…+360n