What is the general solution for 2cos(3x)=-sqrt(3) ?

The general solution for 2cos(3x)=-sqrt(3) is x=(5pi}{18}+(2pin)/3 ,x=(7pi)/(18)+\frac{2pin)/3

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2cos(3x)=-sqrt(3)

2 cos (3 x) = - 3

x = \frac{5 π}{18} + \frac{2 πn}{3}, x = \frac{7 π}{18} + \frac{2 πn}{3}

Solution steps

2 cos (3 x) = - 3

Divide both sides by

2

cos (3 x) = - \frac{3}{2}

General solutions for

cos (3 x) = - \frac{3}{2}

3 x = \frac{5 π}{6} + 2 πn, 3 x = \frac{7 π}{6} + 2 πn

Solve

3 x = \frac{5 π}{6} + 2 πn : x = \frac{5 π}{18} + \frac{2 πn}{3}

Solve

3 x = \frac{7 π}{6} + 2 πn : x = \frac{7 π}{18} + \frac{2 πn}{3}

x = \frac{5 π}{18} + \frac{2 πn}{3}, x = \frac{7 π}{18} + \frac{2 πn}{3}

cos (x) = cos^{2} (x)

- tan (x) = 1

4 sin (3 x) = 7 cos (3 x)

6 sin^{2} (θ) + 13 sin (θ) + 7 = 0

12 sin^{2} (x) - 17 sin (x) + 6 = 0

What is the general solution for 2cos(3x)=-sqrt(3) ?
The general solution for 2cos(3x)=-sqrt(3) is x=(5pi}{18}+(2pin)/3 ,x=(7pi)/(18)+\frac{2pin)/3