What is the general solution for sin(θ)cos(θ)=(sqrt(3))/4 ?

The general solution for sin(θ)cos(θ)=(sqrt(3))/4 is θ= pi/6+pin,θ= pi/3+pin

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sin(θ)cos(θ)=(sqrt(3))/4

sin (θ) cos (θ) = \frac{3}{4}

θ = \frac{π}{6} + πn, θ = \frac{π}{3} + πn

Solution steps

sin (θ) cos (θ) = \frac{3}{4}

Rewrite using trig identities

\frac{sin ( 2 θ )}{2} = \frac{3}{4}

Multiply both sides by

2

sin (2 θ) = \frac{3}{2}

General solutions for

sin (2 θ) = \frac{3}{2}

2 θ = \frac{π}{3} + 2 πn, 2 θ = \frac{2 π}{3} + 2 πn

Solve

2 θ = \frac{π}{3} + 2 πn : θ = \frac{π}{6} + πn

Solve

2 θ = \frac{2 π}{3} + 2 πn : θ = \frac{π}{3} + πn

θ = \frac{π}{6} + πn, θ = \frac{π}{3} + πn

tan (x + \frac{π}{6}) = 3

cos (2 θ) - sin^{2} (θ) = 0

\frac{sin ( 8 0 ^{\circ} )}{5} = \frac{sin ( x )}{4}

2 sin (2 x) + 1 = 0, 0 \leq x \leq 2 π

2 cos (θ) + 3 = 0

What is the general solution for sin(θ)cos(θ)=(sqrt(3))/4 ?
The general solution for sin(θ)cos(θ)=(sqrt(3))/4 is θ= pi/6+pin,θ= pi/3+pin