What is the general solution for tan(2θ)+sqrt(3)=0 ?

The general solution for tan(2θ)+sqrt(3)=0 is θ= pi/3+(pin)/2

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tan(2θ)+sqrt(3)=0

tan (2 θ) + 3 = 0

θ = \frac{π}{3} + \frac{πn}{2}

Solution steps

tan (2 θ) + 3 = 0

Move

3

to the right side

tan (2 θ) = - 3

General solutions for

tan (2 θ) = - 3

2 θ = \frac{2 π}{3} + πn

Solve

2 θ = \frac{2 π}{3} + πn : θ = \frac{π}{3} + \frac{πn}{2}

θ = \frac{π}{3} + \frac{πn}{2}

- 2 sin (θ) + cos (2 θ) = 1

cos (2 x + 60) = sin (3 x)

csc (θ) = - \frac{3}{2}

4 cos (θ) = 0

\frac{sin ( 16 0 ^{\circ} )}{5} = \frac{sin ( c )}{4}

What is the general solution for tan(2θ)+sqrt(3)=0 ?
The general solution for tan(2θ)+sqrt(3)=0 is θ= pi/3+(pin)/2