What is the general solution for tan(θ/8)+sqrt(3)=0 ?

The general solution for tan(θ/8)+sqrt(3)=0 is θ=(16pi)/3+8pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tan(θ/8)+sqrt(3)=0

tan (\frac{θ}{8}) + 3 = 0

θ = \frac{16 π}{3} + 8 πn

Solution steps

tan (\frac{θ}{8}) + 3 = 0

Move

3

to the right side

tan (\frac{θ}{8}) = - 3

General solutions for

tan (\frac{θ}{8}) = - 3

\frac{θ}{8} = \frac{2 π}{3} + πn

Solve

\frac{θ}{8} = \frac{2 π}{3} + πn : θ = \frac{16 π}{3} + 8 πn

θ = \frac{16 π}{3} + 8 πn

sin (\frac{θ}{2}) - 1 = 0, 0 \leq θ \leq 2 π

cos (2 x) = - \frac{2}{2}, 0 \leq x \leq 2 π

\frac{3 + sin ^{2} ( θ )}{cos ( θ ) - 2} = 3 cos (θ)

cos (a) = 0

cos (3 x) = \frac{- 3}{2}

What is the general solution for tan(θ/8)+sqrt(3)=0 ?
The general solution for tan(θ/8)+sqrt(3)=0 is θ=(16pi)/3+8pin