What is the general solution for 0=sin^2(x)-sin(x) ?

The general solution for 0=sin^2(x)-sin(x) is x= pi/2+2pin,x=2pin,x=pi+2pin

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0=sin^2(x)-sin(x)

0 = sin^{2} (x) - sin (x)

x = \frac{π}{2} + 2 πn, x = 2 πn, x = π + 2 πn

Solution steps

0 = sin^{2} (x) - sin (x)

Switch sides

sin^{2} (x) - sin (x) = 0

Solve by substitution

sin (x) = 1, sin (x) = 0

sin (x) = 1 : x = \frac{π}{2} + 2 πn

sin (x) = 0 : x = 2 πn, x = π + 2 πn

Combine all the solutions

x = \frac{π}{2} + 2 πn, x = 2 πn, x = π + 2 πn

cos (2 x) + cos (x) = 2

sec^{2} (θ) + 2 tan (θ) = 0

4 sin^{2} (\frac{x}{2}) + 8 cos (\frac{x}{2}) - 7 = 0

sin (x) + cos (x) = 1, - 36 0^{\circ} \leq x \leq 36 0^{\circ}

5 csc (θ) + 6 = 0

What is the general solution for 0=sin^2(x)-sin(x) ?
The general solution for 0=sin^2(x)-sin(x) is x= pi/2+2pin,x=2pin,x=pi+2pin