What is the general solution for sin(x^2)=1 ?

The general solution for sin(x^2)=1 is x=sqrt((pi+4pin)/2),x=-sqrt((pi+4pin)/2)

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sin(x^2)=1

sin (x^{2}) = 1

x = \frac{π + 4 πn}{2}, x = - \frac{π + 4 πn}{2}

Solution steps

sin (x^{2}) = 1

General solutions for

sin (x^{2}) = 1

x^{2} = \frac{π}{2} + 2 πn

Solve

x^{2} = \frac{π}{2} + 2 πn : x = \frac{π + 4 πn}{2}, x = - \frac{π + 4 πn}{2}

x = \frac{π + 4 πn}{2}, x = - \frac{π + 4 πn}{2}

cos (2 θ) - 3 cos (θ) = 0, 0 \leq θ < 2 π

2 cos^{2} (θ) - 7 cos (θ) - 4 = 0

sin (θ) = \frac{3}{10}, sin (θ + \frac{π}{6})

3 sin^{2} (x) = 8 cos (x)

7 cos (x) - 24 sin (x) = 10

What is the general solution for sin(x^2)=1 ?
The general solution for sin(x^2)=1 is x=sqrt((pi+4pin)/2),x=-sqrt((pi+4pin)/2)