What is the general solution for 9sin(θ)+sqrt(11)=0 ?

The general solution for 9sin(θ)+sqrt(11)=0 is θ=-0.37740…+2pin,θ=pi+0.37740…+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9sin(θ)+sqrt(11)=0

9 sin (θ) + 11 = 0

θ = - 0.37740 \dots + 2 πn, θ = π + 0.37740 \dots + 2 πn

Solution steps

9 sin (θ) + 11 = 0

Move

11

to the right side

9 sin (θ) = - 11

Divide both sides by

9

sin (θ) = - \frac{11}{9}

Apply trig inverse properties

θ = arcsin (- \frac{11}{9}) + 2 πn, θ = π + arcsin (\frac{11}{9}) + 2 πn

Show solutions in decimal form

θ = - 0.37740 \dots + 2 πn, θ = π + 0.37740 \dots + 2 πn

(4 sin (2 x) + 4 cos (2 x))^{2} = 16

2 sec (x) tan (x) + sec^{2} (x) = 0

sec^{2} (x) + 4 tan (x) = 6

sin^{2} (θ) = 4 - 2 cos^{2} (θ)

2 cos^{2} (x) - cos (x) - 3 = 0

What is the general solution for 9sin(θ)+sqrt(11)=0 ?
The general solution for 9sin(θ)+sqrt(11)=0 is θ=-0.37740…+2pin,θ=pi+0.37740…+2pin