What is the general solution for sin^2(x)-cos^2(x)-1=0 ?

The general solution for sin^2(x)-cos^2(x)-1=0 is x= pi/2+pin

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sin^2(x)-cos^2(x)-1=0

sin^{2} (x) - cos^{2} (x) - 1 = 0

x = \frac{π}{2} + πn

Solution steps

sin^{2} (x) - cos^{2} (x) - 1 = 0

Rewrite using trig identities

- 1 - cos (2 x) = 0

Move

1

to the right side

- cos (2 x) = 1

Divide both sides by

- 1

cos (2 x) = - 1

General solutions for

cos (2 x) = - 1

2 x = π + 2 πn

Solve

2 x = π + 2 πn : x = \frac{π}{2} + πn

x = \frac{π}{2} + πn

tan (x) - 1 = - \frac{1}{3} + \frac{1}{3} cot (x)

tan^{2} (x) - 3 tan (x) = 0, 0 \leq x \leq 2 π

75 = 50 cosh (\frac{x}{50})

arcsin (\frac{1}{z}) = 0

3 sin^{2} (θ) - 4 = - 4 sin (θ)

What is the general solution for sin^2(x)-cos^2(x)-1=0 ?
The general solution for sin^2(x)-cos^2(x)-1=0 is x= pi/2+pin