What is the general solution for 2sin(x)=sqrt(3),0<= x<2pi ?

The general solution for 2sin(x)=sqrt(3),0<= x<2pi is x= pi/3 ,x=(2pi)/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2sin(x)=sqrt(3),0<= x<2pi

2 sin (x) = 3, 0 \leq x < 2 π

x = \frac{π}{3}, x = \frac{2 π}{3}

Solution steps

2 sin (x) = 3, 0 \leq x < 2 π

Divide both sides by

2

sin (x) = \frac{3}{2}

General solutions for

sin (x) = \frac{3}{2}

x = \frac{π}{3} + 2 πn, x = \frac{2 π}{3} + 2 πn

Solutions for the range

0 \leq x < 2 π

x = \frac{π}{3}, x = \frac{2 π}{3}

5 csc^{2} (x) + 2.5 cot (x) = 25

sec^{2} (x) + 0.5 tan (x) = 1

8 sin (x) = cos (x) - 3

cos (2 x) - sin^{2} (x) = 1

tan (a) = 4

What is the general solution for 2sin(x)=sqrt(3),0<= x<2pi ?
The general solution for 2sin(x)=sqrt(3),0<= x<2pi is x= pi/3 ,x=(2pi)/3