What is the general solution for 4sin^2(x)+4sin(x)=1 ?

The general solution for 4sin^2(x)+4sin(x)=1 is x=0.20861…+2pin,x=pi-0.20861…+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4sin^2(x)+4sin(x)=1

4 sin^{2} (x) + 4 sin (x) = 1

x = 0.20861 \dots + 2 πn, x = π - 0.20861 \dots + 2 πn

Solution steps

4 sin^{2} (x) + 4 sin (x) = 1

Solve by substitution

sin (x) = \frac{- 1 + 2}{2}, sin (x) = - \frac{1 + 2}{2}

sin (x) = \frac{- 1 + 2}{2} : x = arcsin (\frac{- 1 + 2}{2}) + 2 πn, x = π - arcsin (\frac{- 1 + 2}{2}) + 2 πn

sin (x) = - \frac{1 + 2}{2} :

No Solution

Combine all the solutions

x = arcsin (\frac{- 1 + 2}{2}) + 2 πn, x = π - arcsin (\frac{- 1 + 2}{2}) + 2 πn

Show solutions in decimal form

x = 0.20861 \dots + 2 πn, x = π - 0.20861 \dots + 2 πn

5 cos (t) = 0

2 cos (\frac{x}{2}) = 1

cos (x) = \frac{6}{10}

sec^{2} (x) - 2 tan^{2} (x) = \frac{2}{3}

cos^{2} (x) - 3 cos (x) - 1 = 0

What is the general solution for 4sin^2(x)+4sin(x)=1 ?
The general solution for 4sin^2(x)+4sin(x)=1 is x=0.20861…+2pin,x=pi-0.20861…+2pin