What is the general solution for 2sin(x)+(sin(x))^2=0 ?

The general solution for 2sin(x)+(sin(x))^2=0 is x=2pin,x=pi+2pin

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2sin(x)+(sin(x))^2=0

2 sin (x) + (sin (x))^{2} = 0

x = 2 πn, x = π + 2 πn

Solution steps

2 sin (x) + (sin (x))^{2} = 0

Solve by substitution

sin (x) = 0, sin (x) = - 2

sin (x) = 0 : x = 2 πn, x = π + 2 πn

sin (x) = - 2 :

No Solution

Combine all the solutions

x = 2 πn, x = π + 2 πn

2 cos (x) + 1 = 3, 0 \leq x \leq 2 π

1 - 2 sin (2 x) = 0

2 sin (x) + \frac{1}{sin ( x )} = 0

2 cos^{2} (θ) = 2 + sin (θ)

cos (x) - cos^{3} (x) = 0

What is the general solution for 2sin(x)+(sin(x))^2=0 ?
The general solution for 2sin(x)+(sin(x))^2=0 is x=2pin,x=pi+2pin