What is the general solution for sin(x)cos(x)+sin(x)=0 ?

The general solution for sin(x)cos(x)+sin(x)=0 is x=2pin,x=pi+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin(x)cos(x)+sin(x)=0

sin (x) cos (x) + sin (x) = 0

x = 2 πn, x = π + 2 πn

Solution steps

sin (x) cos (x) + sin (x) = 0

Factor

sin (x) cos (x) + sin (x) : sin (x) (cos (x) + 1)

sin (x) (cos (x) + 1) = 0

Solving each part separately

sin (x) = 0 or cos (x) + 1 = 0

sin (x) = 0 : x = 2 πn, x = π + 2 πn

cos (x) + 1 = 0 : x = π + 2 πn

Combine all the solutions

x = 2 πn, x = π + 2 πn

sin (θ) = 0.56

cos (x) - 5 sin (2 x) = 0

sin (θ) = 0.15

6 cos (2 θ) = 6 cos (θ)

tan (\frac{θ}{2}) = csc^{2} (θ) - cot^{2} (θ)

What is the general solution for sin(x)cos(x)+sin(x)=0 ?
The general solution for sin(x)cos(x)+sin(x)=0 is x=2pin,x=pi+2pin