What is the general solution for tan(θ/2+pi/3)=-1,0<= θ<2pi ?

The general solution for tan(θ/2+pi/3)=-1,0<= θ<2pi is θ=(5pi)/6

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tan(θ/2+pi/3)=-1,0<= θ<2pi

tan (\frac{θ}{2} + \frac{π}{3}) = - 1, 0 \leq θ < 2 π

θ = \frac{5 π}{6}

Solution steps

tan (\frac{θ}{2} + \frac{π}{3}) = - 1, 0 \leq θ < 2 π

General solutions for

tan (\frac{θ}{2} + \frac{π}{3}) = - 1

\frac{θ}{2} + \frac{π}{3} = \frac{3 π}{4} + πn

Solve

\frac{θ}{2} + \frac{π}{3} = \frac{3 π}{4} + πn : θ = 2 πn + \frac{5 π}{6}

θ = 2 πn + \frac{5 π}{6}

Solutions for the range

0 \leq θ < 2 π

θ = \frac{5 π}{6}

- 9 cos^{2} (θ) + 13 = 20 sin (θ)

0 = sin (3 θ)

sec (θ) = \frac{1}{sin ( θ )}

cos (x) = 1, 0 \leq x < 2 π

sin (t) = \frac{1}{3}

What is the general solution for tan(θ/2+pi/3)=-1,0<= θ<2pi ?
The general solution for tan(θ/2+pi/3)=-1,0<= θ<2pi is θ=(5pi)/6