What is the general solution for 8sin(x/2)-8=0 ?

The general solution for 8sin(x/2)-8=0 is x=pi+4pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

8sin(x/2)-8=0

8 sin (\frac{x}{2}) - 8 = 0

x = π + 4 πn

Solution steps

8 sin (\frac{x}{2}) - 8 = 0

Move

8

to the right side

8 sin (\frac{x}{2}) = 8

Divide both sides by

8

sin (\frac{x}{2}) = 1

General solutions for

sin (\frac{x}{2}) = 1

\frac{x}{2} = \frac{π}{2} + 2 πn

Solve

\frac{x}{2} = \frac{π}{2} + 2 πn : x = π + 4 πn

x = π + 4 πn

cos (2 x) + 2 = 3 cos (x)

cos (x) = - cos (2 x)

cos (2 x) + 2 cos (x) = 0

- 1 + cos (x) = 0

cos (x) = - \frac{3}{8}

What is the general solution for 8sin(x/2)-8=0 ?
The general solution for 8sin(x/2)-8=0 is x=pi+4pin