What is the general solution for solvefor θ,3cos(θ-55)=-1.56 ?

The general solution for solvefor θ,3cos(θ-55)=-1.56 is θ=2.11764…+360n+55,θ=-2.11764…+360n+55

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solvefor θ,3cos(θ-55)=-1.56

solve for

θ, 3 cos (θ - 5 5^{\circ}) = - 1.56

θ = 2.11764 \dots + 36 0^{\circ} n + 5 5^{\circ}, θ = - 2.11764 \dots + 36 0^{\circ} n + 5 5^{\circ}

Solution steps

3 cos (θ - 5 5^{\circ}) = - 1.56

Divide both sides by

3

cos (θ - 5 5^{\circ}) = - 0.52

Apply trig inverse properties

θ - 5 5^{\circ} = arccos (- 0.52) + 36 0^{\circ} n, θ - 5 5^{\circ} = - arccos (- 0.52) + 36 0^{\circ} n

Solve

θ - 5 5^{\circ} = arccos (- 0.52) + 36 0^{\circ} n : θ = arccos (- 0.52) + 36 0^{\circ} n + 5 5^{\circ}

Solve

θ - 5 5^{\circ} = - arccos (- 0.52) + 36 0^{\circ} n : θ = - arccos (- 0.52) + 36 0^{\circ} n + 5 5^{\circ}

θ = arccos (- 0.52) + 36 0^{\circ} n + 5 5^{\circ}, θ = - arccos (- 0.52) + 36 0^{\circ} n + 5 5^{\circ}

Show solutions in decimal form

θ = 2.11764 \dots + 36 0^{\circ} n + 5 5^{\circ}, θ = - 2.11764 \dots + 36 0^{\circ} n + 5 5^{\circ}

- 6 sin (c) - 12 = 2 sin (c) - 4

x, 3 cot^{2} (x) - 1 = 0

tan (2 x + 10) = cot (3 x - 15)

tan (θ) = \frac{- 4}{3}

- 2 tan (a) + 2 = 4 tan (a) + 6

What is the general solution for solvefor θ,3cos(θ-55)=-1.56 ?
The general solution for solvefor θ,3cos(θ-55)=-1.56 is θ=2.11764…+360n+55,θ=-2.11764…+360n+55