What is the general solution for cos^2(2x)-1=0 ?

The general solution for cos^2(2x)-1=0 is x=pin,x= pi/2+pin

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cos^2(2x)-1=0

cos^{2} (2 x) - 1 = 0

x = πn, x = \frac{π}{2} + πn

Solution steps

cos^{2} (2 x) - 1 = 0

Solve by substitution

cos (2 x) = 1, cos (2 x) = - 1

cos (2 x) = 1 : x = πn

cos (2 x) = - 1 : x = \frac{π}{2} + πn

Combine all the solutions

x = πn, x = \frac{π}{2} + πn

sin^{2} (x) - 5 sin (x) + 6 = 0

4 = 3 - cot (x) - csc (x)

7 sin (x) tan (x) = 3 tan (x)

sin (2 x) + cos (3 x) = 0

2 cos^{2} (x) + 2 cos (x) - 1 = 0, 0 \leq x \leq 2 π

What is the general solution for cos^2(2x)-1=0 ?
The general solution for cos^2(2x)-1=0 is x=pin,x= pi/2+pin