What is the general solution for 0=2cos(3θ) ?

The general solution for 0=2cos(3θ) is θ= pi/6+(2pin)/3 ,θ= pi/2+(2pin)/3

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0=2cos(3θ)

0 = 2 cos (3 θ)

θ = \frac{π}{6} + \frac{2 πn}{3}, θ = \frac{π}{2} + \frac{2 πn}{3}

Solution steps

0 = 2 cos (3 θ)

Switch sides

2 cos (3 θ) = 0

Divide both sides by

2

cos (3 θ) = 0

General solutions for

cos (3 θ) = 0

3 θ = \frac{π}{2} + 2 πn, 3 θ = \frac{3 π}{2} + 2 πn

Solve

3 θ = \frac{π}{2} + 2 πn : θ = \frac{π}{6} + \frac{2 πn}{3}

Solve

3 θ = \frac{3 π}{2} + 2 πn : θ = \frac{π}{2} + \frac{2 πn}{3}

θ = \frac{π}{6} + \frac{2 πn}{3}, θ = \frac{π}{2} + \frac{2 πn}{3}

(2 sin (2 x) - 1) (tan (2 x) - 3) = 0

3 tan^{2} (θ) - 1 = - 2 tan (θ)

cos (\frac{x}{2}) = \frac{3}{2}, 0 \leq x \leq 2 π

sin (x) = 0.65

sin (x) = 0.78

What is the general solution for 0=2cos(3θ) ?
The general solution for 0=2cos(3θ) is θ= pi/6+(2pin)/3 ,θ= pi/2+(2pin)/3