What is the general solution for 4cos(θ)=-4sin(-θ) ?

The general solution for 4cos(θ)=-4sin(-θ) is θ= pi/4+pin

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4cos(θ)=-4sin(-θ)

4 cos (θ) = - 4 sin (- θ)

θ = \frac{π}{4} + πn

Solution steps

4 cos (θ) = - 4 sin (- θ)

Rewrite using trig identities

4 cos (θ) = 4 sin (θ)

Subtract

4 sin (θ)

from both sides

4 cos (θ) - 4 sin (θ) = 0

Rewrite using trig identities

4 - 4 tan (θ) = 0

Move

4

to the right side

- 4 tan (θ) = - 4

Divide both sides by

- 4

tan (θ) = 1

General solutions for

tan (θ) = 1

θ = \frac{π}{4} + πn

tan (5 x) + tan (3 x) = 0

5 sin (2 x) = 5 cos (x)

2 cos^{2} (x) - 3 cos (x) - 5 = 0

cos (2 x) = - cos (x), 0 \leq x \leq 2 π

2 cos^{2} (w) + 3 cos (w) + 1 = 0

What is the general solution for 4cos(θ)=-4sin(-θ) ?
The general solution for 4cos(θ)=-4sin(-θ) is θ= pi/4+pin