What is the general solution for solvefor x,sin(2x)=-1/2 ?

The general solution for solvefor x,sin(2x)=-1/2 is x=(7pi)/(12)+pin,x=(11pi)/(12)+pin

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solvefor x,sin(2x)=-1/2

solve for

x, sin (2 x) = - \frac{1}{2}

x = \frac{7 π}{12} + πn, x = \frac{11 π}{12} + πn

Solution steps

sin (2 x) = - \frac{1}{2}

General solutions for

sin (2 x) = - \frac{1}{2}

2 x = \frac{7 π}{6} + 2 πn, 2 x = \frac{11 π}{6} + 2 πn

Solve

2 x = \frac{7 π}{6} + 2 πn : x = \frac{7 π}{12} + πn

Solve

2 x = \frac{11 π}{6} + 2 πn : x = \frac{11 π}{12} + πn

x = \frac{7 π}{12} + πn, x = \frac{11 π}{12} + πn

9 cos (2 θ) = 27 cos (θ) - 18

4 csc (x) = 3 csc (x) cot (x) + 3 csc (x)

4 cos^{2} (x) + 4 cos (x) = 1, 0^{\circ} \leq x < 36 0^{\circ}

8 cos^{2} (x) = 4

4 cos (3 x) = 0

What is the general solution for solvefor x,sin(2x)=-1/2 ?
The general solution for solvefor x,sin(2x)=-1/2 is x=(7pi)/(12)+pin,x=(11pi)/(12)+pin