What is the general solution for sin(2x)sin(x)=0,0<= x<= 360 ?

The general solution for sin(2x)sin(x)=0,0<= x<= 360 is x=0,x=90,x=180,x=270,x=360

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sin(2x)sin(x)=0,0<= x<= 360

sin (2 x) sin (x) = 0, 0^{\circ} \leq x \leq 36 0^{\circ}

x = 0, x = 9 0^{\circ}, x = 18 0^{\circ}, x = 27 0^{\circ}, x = 36 0^{\circ}

Solution steps

sin (2 x) sin (x) = 0, 0^{\circ} \leq x \leq 36 0^{\circ}

Solving each part separately

sin (2 x) = 0 or sin (x) = 0

sin (2 x) = 0, 0 \leq x \leq 36 0^{\circ} : x = 0, x = 9 0^{\circ}, x = 18 0^{\circ}, x = 27 0^{\circ}, x = 36 0^{\circ}

sin (x) = 0, 0 \leq x \leq 36 0^{\circ} : x = 0, x = 18 0^{\circ}, x = 36 0^{\circ}

Combine all the solutions

x = 0, x = 9 0^{\circ}, x = 18 0^{\circ}, x = 27 0^{\circ}, x = 36 0^{\circ}

cot^{2} (x) = csc (x) + 1

cos (x) - sin (x) = 0.5

sin (x + π) - sin (x) + 3 = 0

csc (x) = 1.5

tan (t) = 0

What is the general solution for sin(2x)sin(x)=0,0<= x<= 360 ?
The general solution for sin(2x)sin(x)=0,0<= x<= 360 is x=0,x=90,x=180,x=270,x=360