What is the general solution for 1-cot^2(x)=0 ?

The general solution for 1-cot^2(x)=0 is x= pi/4+pin,x=(3pi)/4+pin

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1-cot^2(x)=0

1 - cot^{2} (x) = 0

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

Solution steps

1 - cot^{2} (x) = 0

Solve by substitution

cot (x) = 1, cot (x) = - 1

cot (x) = 1 : x = \frac{π}{4} + πn

cot (x) = - 1 : x = \frac{3 π}{4} + πn

Combine all the solutions

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

cot^{2} (x) - 2 csc^{2} (x) + 5 = 0

3 tan (x) = 3, 0 \leq x < 2 π

cos (x) = \frac{5.3}{8.5}

sin (3 x) = cos (x)

sin (5 x - 1 0^{\circ}) = \frac{2}{2}

What is the general solution for 1-cot^2(x)=0 ?
The general solution for 1-cot^2(x)=0 is x= pi/4+pin,x=(3pi)/4+pin