What is the general solution for 2sin^2(θ)-sin(θ)=3 ?

The general solution for 2sin^2(θ)-sin(θ)=3 is θ=(3pi)/2+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2sin^2(θ)-sin(θ)=3

2 sin^{2} (θ) - sin (θ) = 3

θ = \frac{3 π}{2} + 2 πn

Solution steps

2 sin^{2} (θ) - sin (θ) = 3

Solve by substitution

sin (θ) = \frac{3}{2}, sin (θ) = - 1

sin (θ) = \frac{3}{2} :

No Solution

sin (θ) = - 1 : θ = \frac{3 π}{2} + 2 πn

Combine all the solutions

θ = \frac{3 π}{2} + 2 πn

tan (a) = \frac{5}{4}

4 sin (2 x) - 3 = 0

cos (a) = \frac{5}{13}, e = 5 \cdot (tan (a) + sec (a))

csc (\frac{x}{2}) - 1 = 0

4 cos (x) + 4 sin (x) = 26

What is the general solution for 2sin^2(θ)-sin(θ)=3 ?
The general solution for 2sin^2(θ)-sin(θ)=3 is θ=(3pi)/2+2pin